1 Respuesta
Respuesta de leviatanxxi
1
F (x) = -e^-x(x-2)/x^3
f'(x) = [-e^-x(x-2)/X^3] · {[(-(x-2)+(-x))·x^3 - (-x)·(x-2)·3·x^2]/x^6}=
= [-e^-x(x-2)/X^3] · {[(-x+2-x)·x^3 + x·(x-2) · 3·x^2]/x^6} = simplificando x^3
= [-e^-x(x-2)/X^3] · {[2-2·x + 3·x - 6]/x^3} =
= [-e^-x(x-2)/X^3] · (x-4) /x^3
f'(x) = [-e^-x(x-2)/X^3] · {[(-(x-2)+(-x))·x^3 - (-x)·(x-2)·3·x^2]/x^6}=
= [-e^-x(x-2)/X^3] · {[(-x+2-x)·x^3 + x·(x-2) · 3·x^2]/x^6} = simplificando x^3
= [-e^-x(x-2)/X^3] · {[2-2·x + 3·x - 6]/x^3} =
= [-e^-x(x-2)/X^3] · (x-4) /x^3
