cata_cruz13

Pere Agusti Hontangas respondió: a) N x V = N' x V' ---> [NaOH] = 50 x 0.1 / 30 = 0.167 M b) [OH-] = [NaOH] = 0.167 M [H+] = 10^-14 / 0.167 = 5.99 x 10^-14 pH= -log [H+] =13.22 c) 25 ml x 0.1 mols/1000 ml = 0.0025 mols 30 ml x 0.167 mols/1000 ml = 0.005 mols quedan por neutralizar...