Ftp con PHP
Tengo que realizar un ftp desde el cliente al servidor, se conecta perfecto y me autoriza bien el usuario y la contraseña falla al realizar el ftp. Me podrias decir cual es el error en el codigo?
ftp_put($ftp_conn, "leyesII.htm" , "E:/doc/leyesII.htm", FTP_BINARY)
Gracias
ftp_put($ftp_conn, "leyesII.htm" , "E:/doc/leyesII.htm", FTP_BINARY)
Gracias
1 respuesta
Respuesta de choogal
1
Para subir un archivo de tu disco duro al servidor tienes que hacer antes un formulario para mandar el archivo mendiente un campo input type=file a la pagina donde tendras el codigo de las funciones de ftp.
Te mando un ejemplo:
<html>
<body marginwidth=4 marginheight=4 topmargin=4 leftmargin=4 bgcolor=white vlink="#0000ff" link="#0000ff">
<form name="Attachments" method=POST action="sendimage.php" enctype="multipart/form-data">
<input type=hidden name=box value="">
<tr>
<td nowrap width="1%"> <b>Image:</b></td>
<td colspan=2>
<input type=file name=source_file size=20>
</td>
</tr>
<input type=submit name=btnSubmit value=Submit size=20 style="border: 1px solid #0000FF"></form>
</body>
</html>
The critical point in this form is the usage of enctype="multipart/form-data"
If you don't use this part your upload operations won't work.
Then u must create sendimage.php as follows:
<?php
$ftp_server='190.148.20.201';//serverip
$conn_id = ftp_connect($ftp_server);
// login with username and password
$user="username";
$passwd="*****";
$login_result = ftp_login($conn_id, $user, $passwd);
// check connection
if ((!$conn_id) || (!$login_result)) {
echo "FTP connection has failed!";
echo "Attempted to connect to $ftp_server for user $ftp_user_name";
die;
} else {
echo "
Connected to $ftp_server, for user $user
";
}
//directorylike /www.velibaba.com/images
ftp_chdir($conn_id, "www.velibab.com");
ftp_chdir($conn_id, "compimages");
//$destination_file=ftp_pwd($conn_id);
$destination_file="x.jpg";
echo ("
");
print $destination_file;
echo ("
");
// upload the file
$upload = ftp_put($conn_id, $destination_file, $source_file, FTP_BINARY);
// check upload status
if (!$upload) {
echo "FTP upload has failed!";
} else {
echo "Uploaded $source_file to $ftp_server as $destination_file";
}
// close the FTP stream
ftp_close($conn_id);
?>
Te mando un ejemplo:
<html>
<body marginwidth=4 marginheight=4 topmargin=4 leftmargin=4 bgcolor=white vlink="#0000ff" link="#0000ff">
<form name="Attachments" method=POST action="sendimage.php" enctype="multipart/form-data">
<input type=hidden name=box value="">
<tr>
<td nowrap width="1%"> <b>Image:</b></td>
<td colspan=2>
<input type=file name=source_file size=20>
</td>
</tr>
<input type=submit name=btnSubmit value=Submit size=20 style="border: 1px solid #0000FF"></form>
</body>
</html>
The critical point in this form is the usage of enctype="multipart/form-data"
If you don't use this part your upload operations won't work.
Then u must create sendimage.php as follows:
<?php
$ftp_server='190.148.20.201';//serverip
$conn_id = ftp_connect($ftp_server);
// login with username and password
$user="username";
$passwd="*****";
$login_result = ftp_login($conn_id, $user, $passwd);
// check connection
if ((!$conn_id) || (!$login_result)) {
echo "FTP connection has failed!";
echo "Attempted to connect to $ftp_server for user $ftp_user_name";
die;
} else {
echo "
Connected to $ftp_server, for user $user
";
}
//directorylike /www.velibaba.com/images
ftp_chdir($conn_id, "www.velibab.com");
ftp_chdir($conn_id, "compimages");
//$destination_file=ftp_pwd($conn_id);
$destination_file="x.jpg";
echo ("
");
print $destination_file;
echo ("
");
// upload the file
$upload = ftp_put($conn_id, $destination_file, $source_file, FTP_BINARY);
// check upload status
if (!$upload) {
echo "FTP upload has failed!";
} else {
echo "Uploaded $source_file to $ftp_server as $destination_file";
}
// close the FTP stream
ftp_close($conn_id);
?>
