Respuesta de Lucas m
2
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Hola Andy vera!
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$$\begin{align}&h)\\&\int_{-4}^0 \frac{1}{x+5}= \Bigg[ln |x+5| \Bigg ]_{-4}^0=ln5-ln1=ln5=1.609437912···\\&\\&g) \int_0^2 3^{1-x} dx= \Bigg [\frac{3^{1-x}}{-ln3} \Bigg ]_0^2=\frac{-1}{ln3} \Bigg(3^{-1}-3 \Bigg)=\\&\\&\frac{-1}{ln3} \Bigg( \frac{1}{3}-3 \Bigg)= \frac{-1}{ln3} \Big( \frac{-8}{9} \Big)=\frac{8}{9ln3}=0.809101···\\&\\&\\&\int_{-1}^{1}= \Bigg [x^2+\frac{x^3}{9}-\frac{ x^4}{8} \Bigg]_{-1}^1=1+\frac{1}{9}-\frac{1}{8}- \Big(1-\frac{1}{9}-\frac{1}{8 }\Big)=\\&\\&==\frac{2}{9}\end{align}$$Saludos
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