Tengo una duda con esta derivada?
$$\begin{align}&f (x) = (x-1)^3 √x-1/x+1\end{align}$$f(x)=(x−1)3√x−1/x+1
Respuesta de Karl Mat
1
$$\begin{align}&f(x)=(x-1)^3\sqrt{\frac{x-1}{x+1}}\\&\\&f(x) = \frac{(x-1)^{7/2}}{(x+1)^{1/2}}\\&\\&f'(x)=\frac{[(x-1)^{7/2}]'(x+1)^{1/2} - (x-1)^{7/2}[(x+1)^{1/2}]'}{x+1}\end{align}$$
